Head pressure in hydraulic calculations is expressed by multiplying vertical difference in feet by which constant?

Get ready for the CFD Basic Apparatus and Hydraulics Exam. Study with multiple choice questions that include helpful hints and explanations, ensuring you cover all topics necessary for the exam. Ace your certification with confidence!

Multiple Choice

Head pressure in hydraulic calculations is expressed by multiplying vertical difference in feet by which constant?

Explanation:
Head pressure comes from the weight of a vertical column of liquid, so you use P = γ h, where γ is the fluid’s weight density and h is the height of the column. For water, γ is about 62.4 pounds per cubic foot, and converting to psi per foot gives 62.4 lbf/ft^2 divided by 144 in^2/ft^2, which is 0.433 psi per foot. Rounding to three decimals gives 0.434 psi per foot. So a 1 ft rise adds about 0.434 psi, a 10 ft rise about 4.34 psi, and you’d use a different constant if the fluid isn’t water.

Head pressure comes from the weight of a vertical column of liquid, so you use P = γ h, where γ is the fluid’s weight density and h is the height of the column. For water, γ is about 62.4 pounds per cubic foot, and converting to psi per foot gives 62.4 lbf/ft^2 divided by 144 in^2/ft^2, which is 0.433 psi per foot. Rounding to three decimals gives 0.434 psi per foot. So a 1 ft rise adds about 0.434 psi, a 10 ft rise about 4.34 psi, and you’d use a different constant if the fluid isn’t water.

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